# C program to find all factors of a number

Write a C program to input a number from user and find all factors of the given number using for loop. How to find factors of a number in C program. Logic to find all factors of a given number in C programming.

Example

Input

`Input number: 12`

Output

`Factors of 12: 1, 2, 3, 4, 6, 12`

## Required knowledge

### What is factor of a number?

Factor of any number is a whole number which exactly divides the number into a whole number without leaving any remainder. For example: 2 is a factor of 6 because 2 divides 6 exactly leaving no remainder.

## Logic to find all factors of a number

Step by step descriptive logic to find all factors of a number.

1. Input number from user. Store it in some variable say num.
2. Run a loop from 1 to num, increment 1 in each iteration. The loop structure should look like `for(i=1; i<=num; i++)`.
3. For each iteration inside loop check current counter loop variable i is a factor of num or not. To check factor we check divisibility of number by performing modulo division i.e. `if(num % i == 0)` then i is a factor of num.

If i is a factor of num then print the value of i.

Learn more - Program to find all prime factors of a number.

## Program to find factors of any number

``````/**
* C program to print all factors of a number
*/

#include <stdio.h>

int main()
{
int i, num;

/* Input number from user */
printf("Enter any number to find its factor: ");
scanf("%d", &num);

printf("All factors of %d are: \n", num);

/* Iterate from 1 to num */
for(i=1; i<=num; i++)
{
/*
* If num is exactly divisible by i
* Then i is a factor of num
*/
if(num % i == 0)
{
printf("%d, ",i);
}
}

return 0;
}``````

Output

```Enter any number to find its factors: 100

All factors of 100 are:
1, 2, 4, 5, 10, 20, 25, 50, 100,```

Happy coding 😉 