Write a C program to print all natural numbers from 1 to n using loop. C program to print first n natural numbers using loop. How to print natural numbers in a given range using loop. Logic to print natural numbers using for loop in C program.

**Example**

**Input**

Input upper limit: 10

**Output**

Natural numbers from 1 to 10: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

## Required knowledge

Basic C programming, Relational operators, For loop

## Logic to print natural numbers from 1 to n

There are various ways to print `n` numbers. For this post I am concentrating on `for`

loop to print natural numbers.

Step by step descriptive logic to print natural numbers from 1 to `n`.

- Input upper limit to print natural number from user. Store it in some variable say
`N`. - Run a
`for`

loop from`1`to`N`with`1`increment. The loop structure should be like`for(i=1; i<=N; i++)`

. At this point you might be thinking of various things such as.Why starting from

`1`? Because we need to print natural numbers from`1`.Why going till

`N`? Because we need to print natural numbers up to`N`.Why increment loop counter by

`1`? Because difference between two natural numbers is`1`. Therefore if`n`is one natural number then next natural number is given by`n+1`. - Inside the loop body print the value of
`i`. You might think, why print value of`i`inside loop? Because we need to print natural numbers from`1`to`N`and from loop structure it is clear that`i`will iterate from`1`to`N`. So to print from`1`to`N`print the value of`i`.

Let us code our first loop program.

## Program to print natural numbers from 1 to n

```
/**
* C program to print all natural numbers from 1 to n
*/
#include <stdio.h>
int main()
{
int i, n;
/* Input upper limit from user */
printf("Enter any number: ");
scanf("%d", &n);
printf("Natural numbers from 1 to %d : \n", n);
/*
* Start loop counter from 1 (i=1) and go till n (i<=n)
* increment the loop count by 1 to get the next value.
* For each repetition print the value of i.
*/
for(i=1; i<=n; i++)
{
printf("%d\n", i);
}
return 0;
}
```

Output

Enter any number: 10 Natural numbers from 1 to 10 : 1 2 3 4 5 6 7 8 9 10

## Logic to print natural numbers in range

Using above logic you can easily find a way to print natural numbers in range. If not here is a hint.

- Input start limit from user. Store it in some variable say
`start`. - Input end limit from user. Store it in some another variable say
`end`. - Now, the most important thing to do. Change the above program loop structure. Initialize loop from
`start`that runs till`end`. The loop structure should look like`for(i=start; i<=end; i++)`

.

## Program to print natural numbers in range

```
/**
* C program to print all natural numbers in range
*/
#include <stdio.h>
int main()
{
int i, start, end;
/* Input start and end limit */
printf("Enter start value: ");
scanf("%d", &start);
printf("Enter end value: ");
scanf("%d", &end);
printf("Natural numbers from %d to %d : \n", start, end);
/*
* Start loop counter from start (i=start) and go till
* end (i<=end), increment the loop count by 1 to get
* the next value. For each repetition print the value of i.
*/
for(i=start; i<=end; i++)
{
printf("%d\n", i);
}
return 0;
}
```

Take your programming skills a level further. Learn other approaches to solve this problem.

Learn more -

Output

Enter start value: 10 Enter end value: 15 Natural numbers from 10 to 15 : 10 11 12 13 14 15

Happy coding 😉

### Recommended posts

- Loop programming exercises index.
- C program to find sum of all natural numbers between 1 to n.
- C program to print all even numbers between 1 to n.
- C program to print all odd numbers between 1 to n.
- C program to find sum of all even numbers between 1 to n.
- C program to find sum of all odd numbers between 1 to n.

doubt, write here. I willhelp my best.<pre><code> ----Your Source Code---- </code></pre>