Write a C program to print the given number pattern using loop. How to print the given number pattern of m rows and n columns using for loop in C programming. Logic to print the given number pattern using for loop in C program.
Example
Input
Input rows: 5 Input columns: 5
Output
Required knowledge
Logic to print the given patterns
Before all of these patterns confuse you, I recommend you to learn some basics of number pattern logic.
Once you get acquainted with basics of number pattern printing logic. If you look to these pattern carefully you will find that all of them are similar. Hence if you can decode the logic of any rest of them will be easy to code. Now, have take a minute and look to the below pattern carefully.
If you have looked carefully you can actually divide this pattern in two parts, let me show you.
Now, I hope that logic of whole pattern would have been cleared to you somewhat. If not let me explain the logic to print this pattern.
- To iterate through rows, run an outer loop from 1 to rows (where rows is total rows to be printed).
- To print first part of pattern, run an inner loop from columns to columns – current_row (where columns is total columns to be printed). Inside this loop print the value of current column.
- To print the second part of pattern, run another inner loop from 1 to columns – current_row. Inside this loop print the value of rows – current_row + 1.
Lets implement this…
Note: Logic to all remaining patterns are similar so I won’t be explaining logic of remaining three patterns. But source code of all the three patters are given.
Program to print number pattern 1
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int rows, cols, i, j;
/* Input rows and columns from user
*/
printf("Enter number of rows: ");
scanf("%d", &rows);
printf("Enter number of columns: ");
scanf("%d", &cols);
for(i=1; i<=rows; i++)
{
for(j=cols; j>cols-i; j--)
{
printf("%d", j);
}
for(j=1; j<=cols-i; j++)
{
printf("%d", (rows - i + 1));
}
printf("\n");
}
return 0;
}Output
Enter number of rows: 5 Enter number of columns: 5 55555 54444 54333 54322 54321
Program to print number pattern 2
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int rows, cols, i, j;
/* Input rows and columns from user */
printf("Enter number of rows: ");
scanf("%d", &rows);
printf("Enter number of columns: ");
scanf("%d", &cols);
for(i=rows; i>=1; i--)
{
for(j=1; j<=i-1; j++)
{
printf("%d", i);
}
for(j=i; j<=cols; j++)
{
printf("%d", j);
}
printf("\n");
}
return 0;
}Output
Enter number of rows: 5 Enter number of columns: 5 55555 44445 33345 22345 12345
Program to print number pattern 3
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int rows, cols, i, j;
/* Input rows and columns from user */
printf("Enter number of rows: ");
scanf("%d", &rows);
printf("Enter number of columns: ");
scanf("%d", &cols);
for(i=1; i<=rows; i++)
{
for(j=cols; j>=i; j--)
{
printf("%d", j);
}
for(j=1; j<=i-1; j++)
{
printf("%d", i);
}
printf("\n");
}
return 0;
}Output
Enter number of rows: 5 Enter number of columns: 5 54321 54322 54333 54444 55555
Program to print number pattern 4
/**
* C program to print number pattern
*/
#include <stdio.h>
int main()
{
int rows, cols, i, j;
/* Input rows and columns from user */
printf("Enter number of rows: ");
scanf("%d", &rows);
printf("Enter number of columns: ");
scanf("%d", &cols);
for(i=1; i<=rows; i++)
{
for(j=1; j<=i-1; j++)
{
printf("%d", i);
}
for(j=i; j<=cols; j++)
{
printf("%d", j);
}
printf("\n");
}
return 0;
}Output
Enter number of rows: 5 Enter number of columns: 5 12345 22345 33345 44445 55555
Happy coding 😉