Write a C program to input a number from user and find all factors of the given number using for loop. How to find factors of a number in C program. Logic to find all factors of a given number in C programming.

**Example**

**Input**

Input number: 12

**Output**

Factors of 12: 1, 2, 3, 4, 6, 12

## Required knowledge

Basic C programming, If else, For loop

### What is factor of a number?

Factor of any number is a whole number which exactly divides the number into a whole number without leaving any remainder. For example: 2 is a factor of 6 because 2 divides 6 exactly leaving no remainder.

## Logic to find all factors of a number

Step by step descriptive logic to find all factors of a number.

- Input number from user. Store it in some variable say
`num`. - Run a loop from
`1`to`num`, increment 1 in each iteration. The loop structure should look like`for(i=1; i<=num; i++)`

. - For each iteration inside loop check current counter loop variable
`i`is a factor of`num`or not. To check factor we check divisibility of number by performing modulo division i.e.`if(num % i == 0)`

then`i`is a factor of`num`.If

`i`is a factor of`num`then print the value of`i`.

Learn more – Program to find all prime factors of a number.

## Program to find factors of any number

```
/**
* C program to print all factors of a number
*/
#include <stdio.h>
int main()
{
int i, num;
/* Input number from user */
printf("Enter any number to find its factor: ");
scanf("%d", &num);
printf("All factors of %d are: \n", num);
/* Iterate from 1 to num */
for(i=1; i<=num; i++)
{
/*
* If num is exactly divisible by i
* Then i is a factor of num
*/
if(num % i == 0)
{
printf("%d, ",i);
}
}
return 0;
}
```

Output

Enter any number to find its factors: 100 All factors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, 100,

Happy coding 😉