Write a Java program to input length and width and find perimeter and area of rectangle. Logic to find perimeter and area of a rectangle, whose length and width are given. In this example we will learn to write basic logical program in Java. We will learn to find perimeter and area of rectangle.

**Example**

**Input**

Length of rectangle = 30 Width of rectangle = 20

**Output**

Perimeter of rectangle is 100.0 units. Area of rectangle is 600.0 sq. units.

## Required knowledge

Arithmetic operators, Data types, Basic input/output

## Logic to find perimeter and area of a rectangle

Step by step descriptive logic to find perimeter and area of a rectangle.

- Input length and width of rectangle from user. Store it in some variable say
`length`and`width`. - Apply formula to calculate rectangle perimeter i.e.
`perimeter = 2 * (length + width)`

. - Apply formula to calculate rectangle area i.e.
`area = length * width`

. - Finally, print the value of
`perimeter`and`area`.

## Program to find perimeter and area of rectangle

```
/**
* Java program to find perimeter and area of a rectangle.
*/
import java.util.Scanner;
public class Rectangle {
public static void main(String[] args) {
float length, width, area, perimeter;
// Create scanner class object
Scanner in = new Scanner(System.in);
// Input length and width of rectangle
System.out.print("Enter length of rectangle: ");
length = in.nextFloat();
System.out.print("Enter width of rectangle: ");
width = in.nextFloat();
// Calculate perimeter of rectangle
perimeter = 2 * (length + width);
// Calculate area of rectangle
area = length * width;
// Print perimeter and area of rectangle
System.out.println("Perimeter of rectangle is " + perimeter + " units.");
System.out.println("Area of rectangle is " + area + " sq. units.");
}
}
```

Output

Enter length of rectangle: 30 Enter width of rectangle: 20 Perimeter of rectangle is 100.0 units. Area of rectangle is 600.0 sq. units.

Happy coding ðŸ˜‰