# C program to check even or odd using bitwise operator

Write a C program to input any number and check whether the given number is even or odd using bitwise operator. How to check whether a number is even or odd using bitwise operator in C programming. Logic to check even odd using bitwise operator in C programming.

Example

Input

`Input number: 12`

Output

`12 is even`

## Required knowledge

Must learn this program using other approaches.

## Logic to check even or odd using bitwise operator

Least Significant Bit of an odd number is always set (1). To check whether a number is even or odd we need to figure out if LSB is set or not.

We use Bitwise AND `&` operator to check whether a bit is set or not. Similarly on performing `num & 1` it return LSB of num. If LSB is 1 then the given number is odd otherwise even.

## Program to check even or odd using bitwise operator

``````/**
* C program to check even or odd number using bitwise operator
*/

#include <stdio.h>

int main()
{
int num;

/* Input number from user */
printf("Enter any number: ");
scanf("%d", &num);

if(num & 1)
{
printf("%d is odd.", num);
}
else
{
printf("%d is even.", num);
}

return 0;
}``````

The statement `if(num & 1)` is equivalent to `if((num & 1) == 1)`.

Note: You can also use conditional operator to short the program as done below.

## Program to check even or odd using conditional and bitwise operator

``````/**
* C program to check whether a number is even or odd using bitwise operator
*/

#include <stdio.h>

int main()
{
int num;

/* Input number from user */
printf("Enter any number: ");
scanf("%d", &num);

(num & 1)
? printf("%d is odd.", num)
: printf("%d is even.", num);

return 0;
}``````

Output

```Enter any number: 15
15 is odd.```

Happy coding 😉

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