C program to check even or odd using bitwise operator

Write a C program to input any number and check whether the given number is even or odd using bitwise operator. How to check whether a number is even or odd using bitwise operator in C programming. Logic to check even odd using bitwise operator in C programming.

Example

Input

Input number: 12

Output

12 is even

Required knowledge

Bitwise operators, Data types, Basic input/output, If else

Must learn this program using other approaches.

Learn more -

Logic to check even or odd using bitwise operator

Least Significant Bit of an odd number is always set (1). To check whether a number is even or odd we need to figure out if LSB is set or not.

Even odd using bitwise operator

We use Bitwise AND & operator to check whether a bit is set or not. Similarly on performing num & 1 it return LSB of num. If LSB is 1 then the given number is odd otherwise even.

Even odd using bitwise operator

Program to check even or odd using bitwise operator

/**
 * C program to check even or odd number using bitwise operator
 */

#include <stdio.h>

int main()
{
    int num;

    /* Input number from user */
    printf("Enter any number: ");
    scanf("%d", &num);

    if(num & 1)
    {
        printf("%d is odd.", num);
    }
    else
    {
        printf("%d is even.", num);
    }

    return 0;
}

The statement if(num & 1) is equivalent to if((num & 1) == 1).

Note: You can also use conditional operator to short the program as done below.

Program to check even or odd using conditional and bitwise operator

/**
 * C program to check whether a number is even or odd using bitwise operator
 */

#include <stdio.h>

int main()
{
    int num;

    /* Input number from user */
    printf("Enter any number: ");
    scanf("%d", &num);

    (num & 1) 
        ? printf("%d is odd.", num) 
        : printf("%d is even.", num);

    return 0;
}

Output

Enter any number: 15
15 is odd.

Happy coding 😉

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