Write a C program to check leap year using if else. How to check whether a given year is leap year or not in C programming. C Program to input year from user and check whether the given year is leap year or not using ladder if else. Logic to check leap year in C programming.

**Example**

**Input**

Input year: 2004

**Output**

2004 is leap year.

## Required knowledge

Basic C programming, Arithmetic operators, Relational operators, Logical operators, If else

## Logic to check leap year

Wikipedia states **leap year** as a special year containing one extra day i.e. total 366 days in a year. A year is said to be leap year, if the year is exactly divisible by `4` but and not divisible by `100`. Year is also a leap year if it is exactly divisible by `400`.

Step by step descriptive logic to check leap year.

- Input year from user. Store it in some variable say
`year`. - If
`year`is exactly divisible by`4`and not divisible by`100`, then it is leap year. Or if`year`is exactly divisible by`400`then it is leap year.

Let us now implement the logic in our program.

## Program to check leap year

```
/**
* C program to check Leap Year
*/
#include <stdio.h>
int main()
{
int year;
/* Input year from user */
printf("Enter year : ");
scanf("%d", &year);
/*
* If year is exactly divisible by 4 and year is not divisible by 100
* or year is exactly divisible by 400 then
* the year is leap year.
* Else year is normal year
*/
if(((year % 4 == 0) && (year % 100 !=0)) || (year % 400==0))
{
printf("LEAP YEAR");
}
else
{
printf("COMMON YEAR");
}
return 0;
}
```

Enhance your skills by learning this program using conditional operator.

Learn more - Program to check leap year using conditional operator.

Output

Enter year : 2004 LEAP YEAR

Happy coding 😉

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<pre><code> ----Your Source Code---- </code></pre>