Write a C program to check whether a number is even or odd using if else. How to check whether a number is even or odd using if else in C program. C Program to input a number from user and check whether the given number is even or odd. Logic to check even and odd number using if...else
in C programming.
Input
Input number: 10
Output
10 is even number
Required knowledge
Basic C programming, Arithmetic operators, Relational operators, If else
Logic to check even or odd
A number exactly divisible by 2 leaving no remainder, is known as even number. Programmatically, if any number modulo divided by 2 equals to 0 then, the number is even otherwise odd.
Step by step descriptive logic to check whether a number is even or odd.
- Input a number from user. Store it in some variable say num.
- Check if number modulo division equal to 0 or not i.e.
if(num % 2 == 0)
then the number is even otherwise odd.
Important Note: Do not confuse modulo division operator %
as percentage operator. There is no percentage operator in C.
Read more – Program to calculate percentage.
Let us write program to check even odd.
Program to check even or odd
/**
* C program to check even or odd number
*/
#include <stdio.h>
int main()
{
int num;
/* Input number from user */
printf("Enter any number to check even or odd: ");
scanf("%d", &num);
/* Check if the number is divisible by 2 then it is even */
if(num % 2 == 0)
{
/* num % 2 is 0 */
printf("Number is Even.");
}
else
{
/* num % 2 is 1 */
printf("Number is Odd.");
}
return 0;
}
Advance your programming skills. Learning this program using other approaches.
Output
Enter any number to check even or odd: 11 Number is Odd
Happy coding 😉
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