Write a C program to check whether a number is even or odd using if else. How to check whether a number is even or odd using if else in C program. C Program to input a number from user and check whether the given number is even or odd. Logic to check even and odd number using `if...else`

in C programming.

**Example**

**Input**

Input number: 10

**Output**

10 is even number

## Required knowledge

Basic C programming, Arithmetic operators, Relational operators, If else

## Logic to check even or odd

A number exactly divisible by 2 leaving no remainder, is known as even number. Programmatically, if any number modulo divided by 2 equals to 0 then, the number is even otherwise odd.

Step by step descriptive logic to check whether a number is even or odd.

- Input a number from user. Store it in some variable say
`num`. - Check if number modulo division equal to 0 or not i.e.
`if(num % 2 == 0)`

then the number is even otherwise odd.

**Important Note:** Do not confuse modulo division operator `%`

as percentage operator. There is no percentage operator in C.

Read more - Program to calculate percentage.

Let us write program to check even odd.

## Program to check even or odd

```
/**
* C program to check even or odd number
*/
#include <stdio.h>
int main()
{
int num;
/* Input number from user */
printf("Enter any number to check even or odd: ");
scanf("%d", &num);
/* Check if the number is divisible by 2 then it is even */
if(num % 2 == 0)
{
/* num % 2 is 0 */
printf("Number is Even.");
}
else
{
/* num % 2 is 1 */
printf("Number is Odd.");
}
return 0;
}
```

Advance your programming skills. Learning this program using other approaches.

Output

Enter any number to check even or odd: 11 Number is Odd

Happy coding ðŸ˜‰

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doubt, write here. I willhelp my best.<pre><code> ----Your Source Code---- </code></pre>