Write a C program to input any number and check whether the given number is even or odd using bitwise operator. How to check whether a number is even or odd using bitwise operator in C programming. Logic to check even odd using bitwise operator in C programming.

**Example**

**Input**

Input number: 12

**Output**

12 is even

## Required knowledge

Bitwise operators, Data types, Basic input/output, If else

Must learn this program using other approaches.

Learn more -

## Logic to check even or odd using bitwise operator

Least Significant Bit of an odd number is always set (1). To check whether a number is even or odd we need to figure out if LSB is set or not.

We use Bitwise AND `&`

operator to check whether a bit is set or not. Similarly on performing `num & 1`

it return LSB of `num`. If LSB is 1 then the given number is odd otherwise even.

## Program to check even or odd using bitwise operator

```
/**
* C program to check even or odd number using bitwise operator
*/
#include <stdio.h>
int main()
{
int num;
/* Input number from user */
printf("Enter any number: ");
scanf("%d", &num);
if(num & 1)
{
printf("%d is odd.", num);
}
else
{
printf("%d is even.", num);
}
return 0;
}
```

The statement `if(num & 1)`

is equivalent to `if((num & 1) == 1)`

.

**Note:** You can also use conditional operator to short the program as done below.

## Program to check even or odd using conditional and bitwise operator

```
/**
* C program to check whether a number is even or odd using bitwise operator
*/
#include <stdio.h>
int main()
{
int num;
/* Input number from user */
printf("Enter any number: ");
scanf("%d", &num);
(num & 1)
? printf("%d is odd.", num)
: printf("%d is even.", num);
return 0;
}
```

Output

Enter any number: 15 15 is odd.

Happy coding 😉

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doubt, write here. I willhelp my best.<pre><code> ----Your Source Code---- </code></pre>