Write a C program to enter any number from user and print all even numbers between 1 to n using while loop. C program to display even number in a given range using while loop. How to generate even numbers from 1 to n using while loop in C programming.
Example
Input
Input value of n: 10
Output
Even numbers between 1 to 10: 2, 4, 6, 8, 10
Required knowledge
Basic C programming, If else, While loop
Before moving to this program you must know.
Read more – How to check whether a number is even or odd.
Program to print even numbers using if else
/**
* C program to print all even numbers from 1 to n
*/
#include <stdio.h>
int main()
{
int i, n;
// Input upper limit of even number from user
printf("Print all even numbers till: ");
scanf("%d", &n);
printf("All even numbers from 1 to %d are: \n", n);
/*
* Starts loop counter from 1, increments by 1 till i<=n
*/
i=1;
while(i<=n)
{
/* Check even condition before printing */
if(i%2==0)
{
printf("%d\n", i);
}
i++;
}
return 0;
}Note: As I already mentioned the above method of generating even numbers is not optimal and takes more time to execute. Hence you must use the below method to generate even numbers.
Program to display even numbers without using if statement
/**
* C program to display all even numbers from 1 to n using while loop
*/
#include <stdio.h>
int main()
{
int i, n;
// Input upper limit of even number from user
printf("Print all even numbers till: ");
scanf("%d", &n);
printf("All even numbers from 1 to %d are: \n", n);
i=2; // Since 2 is the first even number
while(i<=n)
{
printf("%d\n", i);
/*
* Adding 2 to current even number will give next even number
*/
i += 2;
}
return 0;
}Check this program using for loop.
Read more – Program to print all even numbers between 1 to n using for loop.
Output
Print all even numbers till: 100 All even numbers from 1 to 100: 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100
Happy coding 😉